12x^2+30x-12=0

Solution for 12x^2+30x-12=0 equation:

12x^2+30x-12=0

a = 12; b = 30; c = -12;
Δ = b2-4ac
Δ = 302-4·12·(-12)
Δ = 1476
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1476}=\sqrt{36*41}=\sqrt{36}*\sqrt{41}=6\sqrt{41}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-6\sqrt{41}}{2*12}=\frac{-30-6\sqrt{41}}{24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+6\sqrt{41}}{2*12}=\frac{-30+6\sqrt{41}}{24}
$